If a circle touches all the four sides of a quadrilateral ABCD at the points P,Q,R,S then prove that AB+CD= BC+AD.
draw a rough diagram
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Answered by
2
this will be rough figure of your question
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![](https://hi-static.z-dn.net/files/dc6/d15c6aaf6420f68f752e4943f0b98523.jpg)
vmin:
pls ask if u are not able to understand any step
Answered by
5
the answer to the question along with diagram and explaination is given
Attachments:
![](https://hi-static.z-dn.net/files/dd3/acdd1cc31914f3083ba99e96f99e978f.jpg)
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