if a circle touches the side BC of a triangle ABC at P and extended sides AB and AC at Q and R respectively prove that PQ =1/2 (BC + CA + AB)
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Answer:
pq=ac/2 by mid point theorem
similarly pr=ab/2
qr=bc/2
pq=pr=qr
pq=1/2(ac+bc+ab)
Step-by-step explanation:
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