Question

If a coa teta - b sin teta = c , prove that ( a sin teta + b coa teta ) = +root a² + b² - c² , -root a²+b²-c².

Answer 1

Hey !!

Given : a cos ¢ - b sin ¢ = c

Now , ( a cos ¢ - b sin ¢)² + b² ( sin ² ¢ + cos ² ¢ ) = a² ( cos ²¢ + sin²¢ ) + b² ( sin²¢ + cos ²¢ ) = a²+b² .

( a cos¢ - b sin ¢ )² + ( a sin¢ + b cos ¢ )² = a² + b².

= c² + ( a sin ¢ + b cos ¢ )² = a² + b² .

=> ( a sin ¢ + b cos¢ ) = +- √a² + b² - c².

Answer 2

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