Question

If a coin is tossed (m + n) times where m > n, Show that the probability of m consecutive heads is .

Answer 1

Answer:

Step-by-step explanation:

So our string of m heads can be in n+1 different positions relative to the other n coin tosses. The outcomes of those n tosses do not matter since your question asks for at least a string of m heads. So the probability should be: (n+1)2n/2n+m.

Answer 2

our string of m heads can be in n+1 different positions relative to the other n coin tosses. The outcomes of those n tosses do not matter since your question asks for at least a string of m heads. So the probability should be: (n+1)2n/2n+m