Question

if a cone height is decreased by 20% and radius is incresed by 20% then what is the percent volume change??? pls answer......... ​

Answer 1

Answer:

according to me the volume will be decreased by 20%

Answer 2

Answer:

let the hight as h and the radius r then the volume will be

$\frac{1}{3} \pi {r}^{2} h$

if the hight decreased by 20% so the hight will be 4/5h

and the radius 6/5r

$\frac{1}{3} \pi { \frac{6r}{5} }^{2} \frac{4}{5} h$

this would be the new volume