Question

IF a constant force of 800 N produces an acceleration of 5 m/s square in a body, what is it's mass? If a body starts from rest, how much distance will it travels in 10 second?

Answer 1

Here your answer goes

Case :- 1

From newton Second law of motion

F = ma

Given ,

Force = 800 N

Acceleration = $5 m/s^{2}$

We know that ,

Force = Mass * Acceleration

⇒ Mass = Force / Acceleration

⇒ 800 / 5

⇒ 160 Kg

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Case :- 2

Given ,

Initial Velocity = 0 m/s ( Starts from Rest )

Acceleration = $5 m/s^{2}$

Time taken by a body = 10 Second

By Second Equation of Motion

$s = ut +\frac{1}{2} at^{2}$

By Substituting the values in the Given Equation

$s = 0 * 10 + \frac{1}{2} * 5 * 10^{2}$

⇒ $s = \frac{1}{2} * 5 * 100$

⇒ $s = \frac{1}{2} * 500$

⇒ $s = \frac{500}{2} \\\\s = 250$

Therefore , the distance travelled by a body is 250 m

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Answer 2

Heya mate...

1)Force = 800 N

Acceleration = 5m/sec ^2

Mass = ?

Force = mass × accekeration

[Tex]\frac{force}{acceleration} = mass [/tex]

[Tex]\frac{800}{5} = mass [/tex]

Msss = 160 kg

2)initial velocity(u) = 0 [ bcs at rest]

Time = 10 seconds

Acceleration = 5m/sec^2

Acceleration = final - initial / time

5 = final/10

Final(v) = 50m/sec

As we know

[Tex] v{}^{2} - u{}^{2} = 2as [/tex]

[Tex] 50{}^{2} = 2(5)(s) [/tex]

[Tex] s=\frac{2500}{10}[/tex]

S=250 m

@skb