If and if angle a:angle b:angle c = 1/2:1/3:1/6 calculate the measure of angle a angle b angle c
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Given :-
In triangle ∆ABC the angles are in a ratio ,
A : B : C = ( 1 / 2 ) : ( 1 / 3 ) : ( 1 / 6 )
To find :-
The measure of angle A , B and C.
Salutation :-
•°• A : B : C = ( 1 / 2 ) : ( 1 / 3 ) : ( 1 / 6 )
= ( 1 / 2 ) × 6 : ( 1 / 3 ) × 6 : ( 1 / 6 ) × 6
= 3 : 2 : 1
Now , let the common Ratio of the following be x.
Then , Angle A = 3x
Angle B = 2x
Angle C = x
So , 3x + 2x + x = 180°
[ ★ Sum of the angles of a triangle is 180° ]
6x = 180°
x = 180° / 6
x = 30°
•°• Angle A ( 3x ) = 3 × 30° = 90°
•°• Angle B ( 2x ) = 2 × 30° = 60°
•°• Angle C ( x ) = 30°
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Verification :-
Angle A + angle B + angle C = 180°
90° + 60° + 30° = 180°
180° = 180°
•°• R.H.S = L.H.S
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