If A= |cosa -sina|
|sina cosa|
then A+A'=1, if the value of
a is
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1
Answer:
Using cos(A+B)=cos(A)cos(B)−sin(A)sin(B), we get
cos(60
o
1
′
)=cos(60
o
)cos(1
′
)−sin(60
o
)sin(1
′
)
=
2
1
−
2
3
×
60
α
....When θ is small and in radian, sinθ=θ and cosθ=1
Step-by-step explanation:
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