Question

If a cricket match is between India and Pakistan and last batsman are there on strike each on 94 runs only 3 balls are remaining and India needs 7 run to win . How is the century of both the batsmen will be completed? You can use any rule of cricket

Answer 1

Answer:

THIS CAN BE DONE ONLY IN 2 BALLS

P1: 94 * ( on strike)

P2: 94* (non-striker)

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Part 1: Let's first solve it on 3 balls:

Ball 1 : P1 hits 6 ( completes his century.)

Ball 2 : P1 hits ball and gets cramp(or ankle twist   or whatever) before completing the single. Other team shows, spirit of game doesn't runs him out. Importantly, players cross.

Ball 3 : Still 1 needed to win, P2 hits six now. ( completes his century . Yay!! )

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Wasn't that tough , right?

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Coming to part 2 , we have to solve it in 2 balls. Here it gets bit tricky!!

Ball 1: P1 hits the ball towards boundary. Batsman run 3 and there are 4 overthrows.

Umpires have a check and found it 1 run short.

Now since they ran 3 , P2 will be on strike. As 1 run was short and overthrow runs are counted in batsman's favor, P1 will get 2 + 4 = total 6 runs, completing his century.

Ball 2 : With still 1 run to get, P2 hits six gets to his century and wins the match for his team :)

HOPE IT IS ENOUGH....

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