Question

if a cube plus b cube plus c cube=3abc find the value of BC/b plus c square plus CA/c plus a square plus ab/a+b square​

Answer 1

Answer:

a^2+b^2+c^2

Step-by-step explanation:

given

a^3+b^3+c^3=3abc;

then a+b+c=0;

bc/b + ca/c + ab/a +a^2+b^2+c^2

=[(c^2ba+a^2bc +b^2ac)/abc] +a^2+b^2+c^2;

=[[abc (a+b+c)]/abc]+a^2+b^2+c^2

=a^2+b^2+c^2(since a+b+c=0)