If a current of 0.5 A flows for 20 minutes in a filament of a bulb, then what would be the
quantity of electrical charge flowing in the circuit?
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I=q/t
I=current in ampere
q=charge in coulombs
t=time in sec
We are given the values:
I= 0.5A
t=20 min= 20×60=1200 sec
q= I × t
=0.5 × 1200 =600 C
I=current in ampere
q=charge in coulombs
t=time in sec
We are given the values:
I= 0.5A
t=20 min= 20×60=1200 sec
q= I × t
=0.5 × 1200 =600 C
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