Question

If a current of 0.5 ampere flows through a metallic wire for two hours . Then how many electrons would flow through the wire.

Answer 1

I == 0.5 A and t= 2hours=7200seconds. Q=It= 0.5×7200=3600Coulomb. number of electrons= Q/ e= 3600/1.6×10^19=2.25×10^22

Answer 2

Hey !!

Q ( coulomb ) = I ( ampere ) × t (s) = ( 0.5 ampere ) ( 2 × 60 × 60 s)

                           = 3600 C

A flow of 96500 C is equivalent to the flow of 1 mole of electrons, 6.02 × 10²³ electrons

 ∴ 3600 C is equivalent to flow of electrons = 6.02 × 10²³ / 96500 × 3600

           = 2.246 × 10²² electrons.

Hope it helps you !!