Question

If a current of 1.5 ampere is maintained in a resistor of 10 ohms then the energy dissipated in 1 minute will be

Answer 1

Hey buddy,

◆ Answer-
H = 1.35 kJ

◆ Explanation-
# Given-
R = 10 ohm
I = 1.5 A
t = 1 min = 60 s

# Solution-
Here, energy is dissipated in form of heat.

Heat energy produced is calculated by -
H = I^2.R.t
H = 1.5^2 × 10 × 60
H = 2.25 × 600
H = 1350 J
H = 1.35 kJ

Therefore, energy dissipated is 1.35 kJ.

Hope it helps you...