if a current of 80 mA flows for 10 seconds find the number of electrons
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Answered by
5
Hlw mate!!
Basic formula to calculate electrons is n = Q/e. e is electron charge which you know already. To determine Q use this I=Q/t which results Q=Ixt.
As you told, I=2A and t=1sec so Q will be Q=2x1= 2 Coloumb
Now n=2/1.6x10^-19 = 1.25x10^19
Hence total 1.25x10^19 electrons are flowing through a wire if 2A current is flowing for 1 sec.
Hope it helpful
Basic formula to calculate electrons is n = Q/e. e is electron charge which you know already. To determine Q use this I=Q/t which results Q=Ixt.
As you told, I=2A and t=1sec so Q will be Q=2x1= 2 Coloumb
Now n=2/1.6x10^-19 = 1.25x10^19
Hence total 1.25x10^19 electrons are flowing through a wire if 2A current is flowing for 1 sec.
Hope it helpful
gamesxd2004a:
in my answer paper it comes 5x10^21 any clue
then tell me exactly hw it becomes 5x10^21
Answered by
8
I=q/t
q=I*t
i=80*10^-3
t=10s
q=8*10^-2*10
q=0.8coulombs
for 1c of charge there are 6.25*10^18 electrons
for 0.8c there are 0.8*6.25.*10^18
no. of electrons= 5*10^19
q=I*t
i=80*10^-3
t=10s
q=8*10^-2*10
q=0.8coulombs
for 1c of charge there are 6.25*10^18 electrons
for 0.8c there are 0.8*6.25.*10^18
no. of electrons= 5*10^19
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