Math, asked by Ziasajid1220, 1 year ago

If A = diag [1, –2, 3] , B = diag [3, 4, –6] , and C = diag [0, 1, 2], find 4A – 2B + 3C.

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Answered by brajeshraja

0

Right answer [ -2 ,-13,30]

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