Question

If a diameter of a circle bisects each of the two chords of circle, then prove that chords are parallel

Answer 1

we know
the radius of a circle bisects a chord at right angles
now
the diameter bisect the two cords .
therefore the cords are perpendicular to the diameter.
hence they are parallel

Answer 2

$\huge\star{\green{\underline{\mathfrak{Answer: -}}}}$

$to \: show \: that \: ab \: is \: parallel \: to \: cd \\ ab \: is \: perpendicular \: to \: ol \\ angle \: alo \: = 90 \: degree \: (equation \: 1) \\ om \: is \: perpendicular \: to \: cd \\ angle \: cmo = 90degree \\ from \: equation \: first \: and \: second \\ angle \: alo \: = ange \: cmo \: = 90 \: degree \\ (consecutive \: pair) \\ ab \: is \: parallel \: to \: cd \: .$