Question

If a dice is thrown once find the probability of getting a number greater than or equal to 4​

Answer 1

Answer:

p(getting no equal to or grater than 4)=no of favorable outcomes/total no of outcomes

ie 3/6=1/2

Answer 2

$\huge\mathcal\pink{ANSWER}$

No. of possible outcomes = 4, 5, 6

$probability = \frac{no.\: of \: possible \: outcome}{total \: no. \: of \: outcomes}$

$= \frac{3}{6}$

$= \frac{1}{2}$

$\huge\mathcal\pink{THANKS}$