if a dice is thrown. what is the probability of getting an odd number
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n(s)=6
Let A be the event that no.come is odd.
A=(1,3,5)
n(A)=3
Therefore P(A)=n(A)/n(s)
=3/6
=1/2
Let A be the event that no.come is odd.
A=(1,3,5)
n(A)=3
Therefore P(A)=n(A)/n(s)
=3/6
=1/2
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