If a dice is tossed, the probability of its upper face bearing an odd number is?
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Answers
Answered by
11
Answer:
1/2
Explanation:
If the dice is rolled
S={1,2,3,4,5,6}
n(S)=6
Event A :No. on the upper face is odd
A=3,5
n(A)=3
p(A)=n(A)/n(S)=3 = 1
6 2
so, P(A)=1/2
Then,
We get =1/2.
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