Question

if a dice is tossed , the probability of its upper face bearing an odd number is ......

Answer 1

3/6 =1/3....
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Answer 2

The dice is rolled
S={1,2,3,4,5,6}
n(S)=6

Event A: No. on the upper face is odd
A={1,3,5}
n(A)=3

P(A)=n(A)/n(S)=3/6=1/2

So,P(A)=1/2