If a dielectric is placed between the two charges in place of vacuum
or air, the force between the charges
a, decreases
b. increases
c. remains unchanged
d. first increases then decreases
Option a
Option b
O Optionc
O Option d
Answers
Answered by
0
Answer:
Correct option is
D
F/4
F=
4πϵ
0
ϵ
r
2
Fd
2
q
1
q
2
Fα
ϵ
r
1
For vacuum ϵ
r
=1,
ϵ
r
of medium =4
∴ F for medium will be F/4.
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