Question

If a discrete r.v. X takes values 0, 1, 2, 3, 4 with probabilities k, 2k, k, 5k, 2k respectvely, the value of k is
А
2/11
B
4/11
C С
1/11
D
5/11​

Answer 1

Answer:

a 211.

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Answer 2

Answer:

The answer is option (C) - 1/11

Explanation:

Given data

               x values   =     0      1       2       3       4  

Probabilities  p(x)    =     k     2k      k       5k     2k    

Here we need to find the value of k  

To find value of k use  ∑ p$_{i}$ = 1   [ as we know sum of probabilities = 1 ]

Therefore,  k+ 2k+ k+ 5k+ 2k  = 1

                                     11 k = 1

                                        k = 1/11

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