Math, asked by nitishmadhepura45, 1 year ago

if a equal to X /(X square + Y square) and b = Y/ ( X square + Y square ). then value of (x + Y) is​

Answers

Answered by sudeeptolodh786
2

Answer:

ab(x^2 + y^2) or abx^2 + aby^2

Step-by-step explanation:

a = x/(x^2 + y^2)

x = a(x^2 + y^2)

b = y/(x^2+y^2)

y = b(x^2+y^2)

So ATP,

x+y

a(x^2 + y^2) + b(x^2+y^2)

ab(x^2 + y^2) or abx^2 + aby^2


nitishmadhepura45: thanks but you have not given full ans....
nitishmadhepura45: ans will come in the term of (a and b) only
sudeeptolodh786: I have also written in term of a and b as ab(x^2+y^2)
sudeeptolodh786: Pls mark me as brainliest pls
sudeeptolodh786: I think that it will not come in term of a and b only
nitishmadhepura45: but ans is in term of a and b only
sudeeptolodh786: Oh .. then i think there should be one more step
sudeeptolodh786: That i have not written
nitishmadhepura45: okkk
Answered by Qwdubai
0

The value of (x + y) is  \frac{a + b } {a^{2} + b^{2} }

Given: a= \frac{x}{x^{2}  + y^{2} }

b= \frac{y}{x^{2} + y^{2} }

To Find: x + y

Solution: Squaring the values of a and b on both sides:

a^{2} = (\frac{x}{x^{2}  + y^{2} })^{2}

b^{2} = (\frac{y}{x^{2}  + y^{2} })^{2}

a^{2} + b^{2} = \frac{x^{2} + y^{2} } {(x^{2} + y^{2})^{2} }

a^{2} + b^{2} = \frac{1 } {(x^{2} + y^{2}) }

By performing cross multiplication,

x^{2} + y^{2}  = \frac{1 } {(a^{2} + b^{2}) }- (Eq1)

From the given values in the question,

x = a(x^{2} + y^{2})

From eq1 we get,

x = a( \frac{1 } {a^{2} + b^{2} })

From the given values in the question,

y = b(x^{2} + y^{2})

From eq1 we get,

y = b( \frac{1 } {a^{2} + b^{2} })

Now adding x and y,

x + y = a( \frac{1 } {a^{2} + b^{2} }) + b( \frac{1 } {a^{2} + b^{2} })

x + y = \frac{a + b } {a^{2} + b^{2} }

#SPJ3

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