Question

If a fish tank is in the form of a cubiod, external measures of that cuboid are 80cm, 40cm,30cm .The base,side faces, and are to be covered with a coloured paper. Find the areas of paper needed.

Answer 1

Surface area of cuboid= 2(lb+bh+lh)
=2{(80×40)+(40×30)+(30×80)} cm^2
= 2{3200+1200+2400}cm^2
= 2{6800} cm^2
= 2×6800cm^2
= 13600cm^2

Answer 2

$\huge \tt Solution↷\:$

• The length of aquarium =l=80cm

• Width of aquarium =b=30cm

• Height of the aquarium= h = 40 cm

• Area of the base = 1 x b = 80 ×30 =2400 cm

• Area of the side face=b×h = 30 ×40 = 1200 cm

• Area of the back face = 1× h = 80×40 = 3200 cm

• Required area = Area of the base + area of the back face+ (2 x area of a side face)

• = 2400 + 3200 + (2 x 1200
• = 8000 cm

• Hence the area of the coloured paper required is 8000 cm².