Question

If a force F=2x+3x.x i N acts along x-axis on an object and moves it from x=2m tox=4m, the work done is. With solution

Answer 1

force=2x+3x.x
X=2 to X=4
work = integration of f.dx
=integration of f.dx under the limit X=2 to
X=4
=integration of (2x+3x.x) under the limit X 2 to X=4
on solving, work=(x x+x.x.x)under the limit x=2 to X=4
putting values of X, work=[80-12]
work=68Nm