Question

If a force F = 2x²y i + 3xy j displaces a particle in the XY-plane from (0,0) to (1, 4) along a curve y = 4x²
then the magnitude of work done is​

Answer 1

Explanation:

We know that,

integral of dw= integral of (F. ds)

Now convert the whole vector into a parameter

't'

So the curve can be written in parameter as

That is put x=t

U get [t, 4t^2]

F=8t^4i+12t^3j

Limit t varies from (0,1)

And dot of it gives W=lt(0,1)[8t^5+48t^5]

Integrating above gives

56(t^6/6)](1,0)

So the answer is (56/6)JOULES...

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Answer 2

Answer:

i hope that u Will understand this