pls answer the question that's at last.
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Step-by-step explanation:
From figure :
In triangle OPX and triangle ORY,
∴ OX = OY [Radius]
=> ∠OPX = ∠ORY
OP = OR [Sides of square]
By side-angle-side criterion of congruence,
ΔOPX ≅ ΔORY
∴ PX = RY
=> PQ - PX = QR - RY [∵ PQ = QR]
=> QX = QY
Hope it helps!
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