Question

if a force of 10 Newton acts on surfaces of areas in the ratio 1 : 2, then the ratio of thrust is?

Answer 1

Hey dear here is your answer

Force = 10 N
Area 1  = x
Area 2 = 2x

Thrust 1 = F / A1 = 10/x
Thrust 2 = F/ A2 = 10/2x = 5/x
Ratio = (10/x) / (5/x) 10 * x / 5 * x = 2/1 = 2 : 1
 

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Answer 2

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Force (F)= 10 N

Ratio of areas = 1 :2

Let the common ratio be x

Area( A1) = x

Area(A2) = 2x
So,

$\bf \: \: thrust \: \: for \: \: area \: \: x \: = \frac{F}{A1} = \frac{10}{a} \\ \\ \bf \: \: thrust \: \: for \: \: area \: \: 2x = \frac{F}{A2} = \frac{10}{2x} \\ \\ so \\ \\ \bf \: \: the \: \: required \: \: ratio \: \: of \: \: thrust \\ \\ \bf \: = \frac{10}{x} : \frac{10}{2x} = 2 : 1$
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