Question

If a force of 120 n is applied to a stationary object of mass 20 kg ,then what would be its velocity after 5 seconds?

Answer 1

$\red{HEY\:BUDDY!!}$

HERE'S THE ANSWER...

______________________________

♠️ Given , Force ( F ) = 120 Newton

⏺️Mass ( m ) = 20 Kg

⏺️Time ( t ) = 5 second

♠️ We know force is product of mass and Acceleration

=> Force = Mass × Acceleration ( a )

=> Acceleration = Force / Mass

=> Acceleration = 120 / 20

=> $\boxed{ Acceleration\:=\:6\: m/s^2}$

♠️ We know change in velocity is know as acceleration

⏺️ Initial velocity ( u ) = 0

⏺️ Final velocity ( v ) = ?

⏺️ Acceleration ( a ) = 6 m/s^2

✔️ Acceleration = ( Final velocity - initial velocity ) / time

=> Acceleration = ( v - 0 ) / 5

=> 6 = v / 5

=> v = 6 × 5

=> $\boxed{Final \: velocity\:=30\:m/s}$


▶️ After 5 second it's velocity will be 30 m/s


HOPE HELPED...

$\red{JAI \:HIND..}$

:)

Answer 2

F = m.a

120 = 20 . a

a = 6 m/s^s

now

v = u + at

v = 0 + 5 . 6

v = 30 m /s