if a force of 50N makes an angle of 30° with two horizontal then find the both vertical and horizontal components of force?
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Answers
Answered by
17
Explanation:
This explanation from Physics/Geometry
60o|
|
| Fy (the vert. comp.)
↑
← 30o_ _ _ _ |
Fx (the horizontal componenet)
F = √(Fx2 + Fy2)
Fy = 50 · cos 60o = 50 · (1/2) = 25 N
Fx = 50 · cos 30o = 50 · (√3)/2 = 25√3 N
I see, that vector sign did not appear in my comment above, so the vector equation is
→ → →
F = 50 cos 30o i + 50 cos 60o j
Bruh...may be this is the ans....✌️✌️
Answered by
24
Explanation:
Given -
- A force of 50 N makes an angle of 30° with horizontal plane.
To Find -
- Find both vertical and horizontal component.
Figure in the attachment.
Now,
As we know that :-
Where the angle θ is located that component is known as cos
And other component is known as sin
Here,
50 N makes an angle of 30° with horizontal component so, horizontal component is 50 cos30° and the vertical component is 50 sin30°
As we know that :-
cos30° = √3/2, and
sin30° = 1/2
Then,
50 cos30° = 50 × √3/2 = 25√3 N
And
50 sin30° = 50 × 1/2 = 25 N
Hence,
The horizontal component of force is of 25√3 N
and
The vertical component of force is of 25 N
Attachments:
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