If a function f (x)=(3x-2)/2 has domain (2,4,6) find the range
Answers
Answered by
0
Answer:
Lalalalalalallalalalalalallalalal
Answered by
1
Step-by-step explanation:
f(x) = (3x - 2) / 2
f(2) = (3(2) - 2) /2
= (6-2) /2
= 4/2
= 2
f(4) = (3(4) - 2) /2
= (12-2) /2
= 10/2
= 5
f(6) = (3(6) - 2) /2
= (18-2) /2
= 16/2
= 8
Range = {2,5,8}
Similar questions