Question

If a gas in a closed container is pressurized from 1.5 atm to 1.6 atm and its original temperature was 298 K, what would be the final temperature of the gas?

Answer 1

since pressure is proportional to the temperature, it'll be T1/P1=T2/P2

now solve it by putting the values..

it's the basic laws

Answer 2

HERE COMES YOUR ANS MATE:-

FROM FORMULA WE HAVE :-

P1V1 / T1 = P2V2 /T2

BY KEEPING V CONSTANT WE HAVE:-

P1/ T1 = P2 /T2

P1= 1.5 ATM

P2= 1.6 ATM

T1= 298K

PUTTING THE VALUES:-

P1 / T1 = P2 / T2

BY CROSS MULTIPLYING WE GET:-

T2= P2T1/ P1

BY PUTTING VALUES WE GET

T2 = 298 k