Question

If a geostationary satellite is orbiting the earth at a height of 6R above the surface of the Earth R being the radius of the Earth then what will be the time period of another satellite of height 2.5R from the surface of the earth?

Answer 1

please see the attachment 

and for geostationary satellite T = 24 hr
 so T2 = 24/2√2 = 6√2 hr

Answer 2

Distance of satellite from centre of earth are 7 R and 2.5 R respectively.

Time period of geostationary satellite is 24 hours.

We know

T2/T1 = ( R2/R1)^3/2

T2 = 24 (2.5R/7R)^3/2

T2 = 6√2 h.

By

Sonam Tyagi