If a girl cycles at 10 kmph, then she arrives at a certain place at 1 p.m. If she cycles at 15 kmph, she will arrive at the same place at 11 a.m. At what speed must she cycle to get there at noon?
A) 14 kmph
B) 13 kmph
C) 12 kmph
D) 11 kmph
Answers
Answered by
0
☆☞ Here is ur answer ☜☆
✔✔ The distance is constant in this case.
Let the time taken for travel with a speed of 10 kmph be 't'.
Now the speed of 15 kmph is 3/2 times the speed of 10 kmph.
Therefore, time taken with the speed of 15 kmph will be 2t/3 (speed is inversely proportional to time)
Extra time taken = t - 2t/3 = t/3
=> 1pm - 11am = 2hrs
=> t/3 = 2h
=> t = 6 hrs.
Now, Distance = speed x time = 10 x 6 = 60 kms
Time he takes to reach at noon = 6 - 1 = 5 hrs
Now, Speed = 60/5 = 12 kmph.
HOPE IT HELPS!
Answered by
11
Extra time taken = t - 2t/3 = t/3
:-1pm - 11am = 2hrs
:-t/3 = 2h
;- t = 6 hrs.
Distance = speed x time
= 10 x 6
= 60 kms
Time he takes to reach
= 6 - 1
= 5 hrs
Speed = 60/5 = 12 kmph.
thanks me Later ❤️
:-1pm - 11am = 2hrs
:-t/3 = 2h
;- t = 6 hrs.
Distance = speed x time
= 10 x 6
= 60 kms
Time he takes to reach
= 6 - 1
= 5 hrs
Speed = 60/5 = 12 kmph.
thanks me Later ❤️
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