Question

if a human heart beats once in every 0.8 s.find the no. of times it has beating in life of a 10 year old boy.

Answer 1

Given : 0.8 s no on time 1

To Find : in a whole life of 10 years old child

Solution :

1 year =365 days

10 year = 10 × 365 days

1 day = 24 hr

3650 days = 3650×24 hr

1 hr = 60 min

3650×24 hr= 3650×24×60 min

1 min =60 sec

3650×24×60 min= 3650×24×60×60sec

Total time in sec = 315360000

0.8 sec = 1 time

No. of times in 315360000 sec= 315360000/.8

=394200000

result is 394200000

Answer 2

Answer:

A human heart beats 39,42,00,000 times in a 10 year old boy's life.

Explanation:

As per the data given in the question,

We have,

Time taken for human heart to beat = 0.8 sec

No. of time it beats each minute = $\frac{60}{0.8} = 75$

No. of time it beats each hour = $75\times60=4500$

No. of time it beats each day = $4500\times24= 108000$

No. of time it beats each year= $108000\times365=39420000$

No. of time it beats in 10 year= $39420000\times 10=39,42,00,000$

hence,

A human heart beats 39,42,00,000 times in a 10 year old boy's life.

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