Question

If A = i+j+k , then what is the unit vector along A? i will report if its wrong trust me i do what i say

Answer 1

Explanation:

Vector (P-Q) = (i+j-k)-(i-j+k) = 2.j - 2.k.

|P-Q| = √{(2)^2+(-2)^2} = 2.√2 units.

Unit vector along (P-Q) = vector (P-Q)/|P-Q|.

= (2.j - 2.k)/2.√2 = (1/√2).( j - k ). Answer.

$\huge \purple{\mid{\underline{\overline{\textbf{❥ᴘʟs ғᴏʟʟᴏᴡ\:᭄}}}\mid}}$

Answer 2

Answer:

Vector (P-Q) = (i+j-k)-(i-j+k) = 2.j - 2.k.

|P-Q| = √{(2)^2+(-2)^2} = 2.√2 units.

Unit vector along (P-Q) = vector (P-Q)/|P-Q|.

= (2.j - 2.k)/2.√2 = (1/√2).( j - k ). Answer.

\huge \purple{\mid{\underline{\overline{\textbf{❥ᴘʟs ғᴏʟʟᴏᴡ\:᭄}}}\mid}}∣

❥ᴘʟs ғᴏʟʟᴏᴡ᭄

∣

Explanation:

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