Question

If (a+ib)^2=(1+4√3i), then prove that ((a)^2-(b)^2)=1 and ab=2√3.​

Answer 1

Step-by-step explanation:

(a+ib)² = a²-b²+2iab

given , (a+ib)² = 1+4√3i

so, a²-b² + 2abi = 1 +4√3i

by comparing real part and complex part,

a²-b² = 1

2ab = 4√3 so, ab =2√3

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