Math, asked by ksran2885gmailcom, 1 year ago

if a+ib= (x+i)²/2x² + 1.. prove that a²+ b²= (x²+1)²/(2x²+1)².

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Answered by saurabhsemalti
31

a + ib =  \frac{(x + i) {}^{2} }{(2x {}^{2}  + 1) {}^{2} }  \\ taking \: rhs \:  \\  =  \frac{ {x}^{2} +  {i}^{2} + 2xi  }{4 {x}^{4} + 1 + 4 {x}^{2}  }  \\  a + ib=  \frac{ {x}^{2}  - 1}{(2 {x}^{2} + 1) {}^{2}  }  + i \:  \frac{2x}{(2 {x}^{2} + 1) {}^{2}  }  \\ compare \\ a =  \frac{ {x}^{2} - 1 }{(2 {x}^{2} + 1) {}^{2}  }  \\ b =  \frac{2x}{(2 {x}^{2}  + 1) {}^{2} }  \\  {a}^{2}  +  {b}^{2}  \\  =  \frac{( {x}^{2} - 1) {}^{2}  }{(2 {x}^{2} + 1) {}^{4}  }  +  \frac{4x {}^{2} }{(2 {x}^{2} + 1) {}^{4}  }  \\  =  \frac{( {x}^{2}  + 1) {}^{2} }{(2 {x}^{2} + 1) {}^{4}  }


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Answered by pravanti
4

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