if a if a + b + c is equal to 10 and a square+ b square + c square =83 find the value of a cube+ bcube + c cube -3abc
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a+b+c=10......(1)
squaring both sides in (1)
(a+b+c)²=(10)²
a²+b²+c²+2ab+2bc+2ac=100
83+2(ab+bc+ac)=100
2(ab+bc+ac)=100-83
2(ab+bc+ac)=17
ab+bc+ac=17/2
we know that,
a³+b³+c³-3abc=(a+b+c) (a²+b²+c²-ab-bc-ac)
=(10) (83-17/2)
=745
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