Question

if (A intersction B)= nill,then n(AuB)=n(A)+n(B)
solve it please

Answer 1

Answer:

Step-by-step explanation:

We know that n(AuB) = n(A) + n(B) - n(AnB)

n(AnB) = 0 (given)

n(AuB) = n(A) + n(B) - n(AnB)

=>  n(AuB) = n(A) + n(B).

Hence proved