if a is 2 plus root 3 by 2 find asquare plus 1 by asquare
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Answer:
Given :-
y = 2 + √3
Have To Find Out :-
Value of (y + 1/y) & (y² + 1/y²)
Using Property :-
a² + 1/a² = (a + 1/a)² - 2
Explanation :-
=> y + 1/y
=> (2 + √3) + 1/(2 + √3)
=> {(2 + √3)² + 1 } / (2 + √3)
=> {4 + 3 + 4√3 + 1}/ (2 + √3)
=> (8 + 4√3) / (2 + √3)
=> 4(2 + √3) / (2 + √3)
=> 4
y + 1/y = 4
Now ,
y² + 1/y² = (y + 1/y)² - 2
= (4)² - 2
= 16 - 2
= 14
Result :-
(1) (y + 1/y) = 4
(2) (y² + 1/y²) = 14
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