If a is 20% more than c and b is 60% more than c then a is what percentage of b?
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Let, the value of c be, 'x'
a = x+(x*20/100)
= x+ x/5
= (5x+x)/5
= 6x/5
b = x+(x*60/100)
= x+ 3x/5
= (5x+3x)/5
= 8x/5
So, a is {(6x/5)/(8x/5)}*100
= (6x*5*100/8x*5)
=(3*100/4)
= (3*25)
= 75% of b
(Ans): 75%
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