Question

If A is (-3,4) and B is (2,-1) find the equation of a point B which is equidistant from both the points A and B. interpret the lotus geometrically.​

Answer 1

Step-by-step explanation:

Let A≡(−2,3) and B≡(6,−5)      

Let the required point be P(x,y).

ax+by+c=0     ...(1)

PA  

2

=PB  

2

          ....Given

By distance formula,

(x+2)  

2

+(y−3)  

2

=(x−6)  

2

+(y+5)  

2

 

4x+4+9−6y=−12x+36+10y+25

x−y−3=0     ...(2)

Comparing eq (1) and (2), we get

a=1;b=−1,c=−3  

Ascending order : c,b,a