Question

If a is a constant such that 4x^2 - 12x + a is the square of a binomial, then what is a?

Answer 1

Answer:

a=9

Step-by-step explanation:

Equation: $4x^{2} -12x+a$

Convert it to perfect square binomial: $\left(2x-3\right)^2$

FOIL it: $4x^2-12x+9$

Therefore:

a=9

Answer 2

Answer:

your answer is

[2x-1]^2

Step-by-step explanation:

4x^2-4x+1

=[2x]^2+2[2x]*[-1]+[-1]^2

=[2x-1]^2