If a is a natural number then the remainder when (5a + 1) (5a + 3) (5a + 4) is divided by 5,is
a) 0
b) 1
c) 2
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Now we shall use trile and error method:
Let a be 1
=((5×1+1)(5×1+3)(5×1+4))÷5
=(6×8×9)÷5
=432÷5
The remainder is 2
Let a be 2
=((5×2+1)(5×2+3)(5×2+4))÷5
=(11×13×14)÷5
=2002÷5
The remainder is 2
Let a be 3
=((5×3+1)(5×3+3)(5×3+4))÷5
=(16×18×19)÷5
=5472÷5
The remainder is 2
So the answer is 2
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