If a is a square matrix of order 2 and |A| = 3 find:
(i) |adj A| =
(ii) |a(adjA)| =
(iii) A(adj A) =
(iv) |4A| =
(v) det
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We know that.
∣Adj(AdjA)∣=∣A∣(n−1)2
n→ order of the square matrix.
⇒∣Adj(AdjA2)∣=∣A2∣(n−1)2
Given n=3
⇒∣Adj(AdjA2)∣=∣A2∣(2)2
=∣A∣8
⇒∣Adj(AdjA2)∣=∣A∣8
Hence, A8 is the correct answer.
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