if A is a square matrix of order 3 such that |A| = 5 , find |A.adjA| .
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Answer:
Given matrix A of order n, A−1=adj(A)|A|;
We know that, A⋅A−1=I
⇒A⋅(adj(A)|A|)=I
⇒A⋅adj(A)=|A|⋅I
⇒|A⋅adj(A)|=|A|n
⇒|A|⋅|adj(A)|=|A|n
⇒|adj(A)|=|A|n−1
Therefore, here |adj(A)|=52=25
Step-by-step explanation:
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