If A is a square matrix of order 3 x 3 and Aij is the cofactor of then aij, then a11A11+a12A12+a13A13=
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Answered by
16
Answer:
Answer:
Since the matrix is of order 3 x 3, so the value of n x n is also 3.
Given that the determinant of the given matrix is 4.
|A| = 4
We've to find the value of a function equals to |3*A|
Consider that A be the 3 x 3 order matrix and its value is;
n^n*|A| = 3³ *4 = 27 *4 = 108
|3*A| = 108
Answer.
Answered by
3
Answer:
Since the matrix is of order 3 x 3, so the value of n x n is also 3. Given that the determinant of the given matrix is 4. Answer
Correct option is
A
8
a
11
A
11
+a
12
A
12
+A
13
A
13
=3
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2
2
1
6
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−2
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1
3
1
6
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+4
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1
3
2
2
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=3(12−2)−2(6−3)+4(2−6)
=30−6−16
=8
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