Question

if A is a square matrix of order3 such that |adj A|=36,then what is the value of |A^T|?​

Answer 1

✔Solution:

A is non-singular matric of order 3 then...⬇ (n=3)

$|adjA| = | {A}^{n - 1} |$

given that...

$|adjA| = 36 \\ |adjA| = {6}^{2} \\ { |A| }^{3 - 1} = {6}^{2} |by \: the \: above \: theorem| \\ { |A| }^{2} = {6}^{2} \\ |A| = 6$

Determinant of the transpose is equal to the determinate of the matric..

${ |A| }^{1} = 6$

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Answer 2

bahut muskil question hai

sorry