If A is acute and cos A=4/5 then sin A =?
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Answer:
90 4/5
90 4/5 a 18 is the correct answer is present
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Hey there!
Cos A = 4/5
Base / Hypotenuse = 4 / 5
Let base be 4x and hypotenuse be 5x,
By Pythagoras theorem :
hypotenuse² = height ² + base²
( 5x )² = height² + ( 4x )²
25x² = height² + 16x²
9x² = height²
3x = height
Hence,
SinA = height / hypotenuse
= 3x / 5x
= 3/5
Hope it helps! :)
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